Home
Class 11
PHYSICS
The equation of a wave travelling on a s...

The equation of a wave travelling on a string is `y = (0.10 mm) sin [(31.4 m^(-1)) x + (314 s^(-1))t]`
(a) In which direction does the travel?
(b) Find the wave speed, the wavelength and the frequency of the wave.
( c ) What is the maximum displacement and the maximum speed of a portion of the string?

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
(a) coefficient of `x and t` are same sign.
(b) `v = (31.4)/(31.4)=10 m//s rArr lambda =(2pi)/(k), f = (omega)/(2pi)`
( c ) `v_(max) = omegaA`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • WAVE MOTION

    DC PANDEY ENGLISH|Exercise Exercise 17.4|2 Videos

  • WAVE MOTION

    DC PANDEY ENGLISH|Exercise Exercise 17.5|6 Videos

  • WAVE MOTION

    DC PANDEY ENGLISH|Exercise Exercise 17.2|2 Videos

  • VECTORS

    DC PANDEY ENGLISH|Exercise Medical enrances gallery|9 Videos

  • WORK, ENERGY & POWER

    DC PANDEY ENGLISH|Exercise Level 2 Comprehension Based|2 Videos

Similar Questions

Explore conceptually related problems

The equation of a wave travelling on a string is y=(0.10mm)sin[3.14m^-1)x+(314s^-1)t] . (a) In which direction does the wave travel ? (b) Find the wave speed, the wavelength and the frequency of the wave. (c) What is the maximum displacement and the maximum speed of a portion of the string ?

The equation of a travelling wave on a string is y = (0.10 mm ) sin [31.4 m^(-1) x + (314s^(-1)) t]

Knowledge Check

  • The equation of a wave travelling in a string can be written as y = 3 cos pi (10t-x) . Its wavelength is

    A
    100 cm
    B
    2 cm
    C
    5 cm
    D
    none of the above

    • Similar Questions

    Explore conceptually related problems

    The equation of a wave travelling on a string is given by Y(mn) = 8 sin[ (5m^(-1)x-(4s^(-1)t ]. Then

    The equation for a wave travelling in x-direction 0n a string is y = (3.0 cm) sin [(3.14 cm^(-1) x -(314 s^(-1)t] (a) Find the maximum velocity of a particle of the string. (b) Find the acceleration of a particle at x = 6.0 cm at time t = 0.11 s

    The equation for a wave travelling in x-direction on a string is y = (3.0cm)sin[(3.14 cm^(-1) x - (314s^(-1))t] (a) Find the maximum velocity of a particle of the string. (b) Find the acceleration of a particle at x =6.0 cm at time t = 0.11 s.

    The equational of a stationary wave in a string is y=(4mm) sin [(314m^(-1)x] cos omegat . Select the correct alternative (s).

    The equetion of a wave travelling on a string is y = 4 sin(pi)/(2)(8t-(x)/(8)) if x and y are in centimetres, then velocity of waves is

    The equetion of a wave travelling on a string is y = 4 sin(pi)/(2)(8t-(x)/(8)) if x and y are in centimetres, then velocity of waves is

    The equation of a wave travelling on a string stretched along the X-axis is given by y=Ae^(((-x)/(a) + (t)/(T))^(2) (a) Write the dimensions of A, a and T. (b) Find the wave speed. (c) In which direction is the wave travelling? (d) Where is the maximum of the pulse located at t =T and at t = 2T ?

    Home
    Profile