Home
Class 10
PHYSICS
The moment of a force of 10N about a fix...

The moment of a force of 10N about a fixed point O is 5 Nm. Calculate the distance of the point O from the line of action of the force.

Text Solution

AI Generated Solution

To solve the problem, we will use the formula for the moment of a force about a point. The moment (or torque) is given by the equation: \[ \text{Moment} = \text{Force} \times \text{Perpendicular Distance} \] Given: - Moment of the force (M) = 5 Nm - Force (F) = 10 N ...
Promotional Banner

Topper's Solved these Questions

  • FORCE

    ICSE|Exercise EXERCISE 1B |11 Videos
  • FORCE

    ICSE|Exercise EXERCISE 1(B) Multiple choice questions|2 Videos
  • FORCE

    ICSE|Exercise EXERCISE 1(A) Multiple choice questions|2 Videos
  • ELECTRO-MAGNETISM

    ICSE|Exercise EXERCISE-10 (C) NUMERICALS |1 Videos
  • HOUSEHOLD CIRCUITS

    ICSE|Exercise EXERCISE -9(B) (MULTIPLE CHOICE TYPE)|2 Videos

Similar Questions

Explore conceptually related problems

The moment of a force of 5N about a point P is 2 Nm. Calculate the distance of point of application of the force from the point P.

The moment of a force of 50 N about a point is 5 Nm. Find the perpendicular distance of force from that point.

Let a force F be acting on a body free to rotate about a point O and let r the position vector of any point P on the line of action of the force. Then torque (tau) of this force about point O is defined as tau = rxxF Given, F = (2hati + 3hatj - hatk)N and r = (hati- hatj+6hatk)m Find the torque of this force.

Let a force F be acting on a body free to rotate about a point O and let r the position vector of ant point P on the line of aciton of the force. Then torque (tau) of this force abot point O is defined as tau = rxxF Given, F = (2hati + 3hatj - hatk)N and r = (hati- hatj+6hatk)m Find the torque of this force.

The moment of the force F acting at a point P, about the point C is

The moment of inertia of a uniform rod of mass 0.50 kg and length 1 m is 0.10 kg m^2 about a line perpendicular to the rod. Find the distance of this line from the middle point of the rod.

The magnitude of torque on a particle of mass 1 kg is 2.5 Nm about the origin.If the force acting it is 1 N, and the distance of the particle from the origin is 5 m, the angle between the force and the position vector is (in radians):

The property of the electric line of force (a) The tangent to the line of force at any point is parallel to the direction of .E. at that point (b) No two lines of force intersect each other

If the Mechanical Advantage of a lever of 100 , when a force of 10N acts as a distance of 20cm from the point of fulcrum. Calculate the force acting on the other side of the fulcrum and the distance of that force from the fulcrum.

Two fixed, equal, positive charges, each of magnitude 5xx10^-5 coul are located at points A and B separated by a distance of 6m. An equal and opposite charge moves towards them along the line COD, the perpendicular bisector of the line AB. The moving charge, when it reaches the point C at a distance of 4m from O, has a kinetic energy of 4 joules. Calculate the distance of the farthest point D which the negative charge will reach before returning towards C.

ICSE-FORCE -EXERCISE 1(A) Numericals
  1. The moment of a force of 10N about a fixed point O is 5 Nm. Calculate ...

    Text Solution

    |

  2. A nut is opened by a wrench of length 10cm. IF the least force require...

    Text Solution

    |

  3. A wheel of diameter 2m is shown in Fig 1.28 with axle at O. At force F...

    Text Solution

    |

  4. The diagram in Fig.1.29 shows two forces F1=5N and F2=3N acting at poi...

    Text Solution

    |

  5. The forces each of magnitude 10N act vertically upwards and downwards ...

    Text Solution

    |

  6. Fig.1.31 shows two forces each of magnitude 10N acting at points A and...

    Text Solution

    |

  7. A steering wheel of diameter 0.5m is rotated anticlockwise by applying...

    Text Solution

    |

  8. A uniform metre rule is pivoted as its mid point. A weight of 50gf is ...

    Text Solution

    |

  9. A uniform metre rule between horizontally on a knife edge placed at th...

    Text Solution

    |

  10. The diagram below (Fig.1.32) shows a uniform bar supported at the midd...

    Text Solution

    |

  11. Fig.1.33 shows a uniform metre rule placed on a fulcrum at its mid poi...

    Text Solution

    |

  12. When a boy weighing 20 kgf sits at one end of a 4m long see saw, if ge...

    Text Solution

    |

  13. A physical balance has its arms of length 60cm and 40cm. What weight k...

    Text Solution

    |

  14. The diagram in Fig.1.34 shows a uniform metre rule weighing 100gf, piv...

    Text Solution

    |

  15. A uniform metre rule of weight 10gf is pivoted at its 0 mark. (i) Wh...

    Text Solution

    |

  16. A uniform half metre rule can be balanced at the 29.0cm mark when a ma...

    Text Solution

    |

  17. A uniform metre rule of mass 100g is balanced on a fulcrum at mark 40c...

    Text Solution

    |

  18. In Fig.1.35 a uniform bar of length l m is supported at its ends and l...

    Text Solution

    |