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Isotherms of carbon dioxide at various t...

Isotherms of carbon dioxide at various temperatures are repersented in figure. Answer the following questions based on this figures.

(i) In which state will `CO_(2)` exist between the points a and b at temperature `T_(1)` ?
(ii) At what point will `CO_(2)` start liquefyinh when temperature is `T_(1)` ?
(iii) At what point will `CO_(2)` be completely liquefued when temperature is `T_(2)` ?
(iv) Will condensation take place when the temperature is `T_(3)` ?
(v) What portion of the isotherm at `T_(1)` represent liquid and gaseous `CO_(2)` at equilibrium ?

Text Solution

Verified by Experts

The correct Answer is:
1682.5 K, 2143.4 K
The average velocity of a gas is given by
`baru =sqrt((8RT)/(piM))`
In the present case, `baru =9.0xx10^4 " cm " s^(-1)`,
`R=8.314xx10^7 " erg " K^(-1) mol^(-1)`
`T=T_1 (?) and M=44`
`:. " " 9.0xx10^4=sqrt((8xx8.314xx10^7xxT_1)/(3.14xx44))`
Hence, `T_1 = 1682.5 K`.
The most probable velocity is given by
`alpha = sqrt((2RT)/M)`
`:. " " 9.0xx10^4=sqrt((2xx8.314xx10^7xxT_2)/(44))`
Which gives `T_2 = 2143.3 K`.
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