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The length, breadth and height of a rect...

The length, breadth and height of a rectangular solid are in the ratio `5: 4, 2`. If the total surface area is `1216cm^(2)`, find the length, the breadth and the height of the solid.

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To solve the problem, we need to find the dimensions of a rectangular solid (cuboid) given the ratio of its length, breadth, and height, as well as its total surface area. ### Step-by-Step Solution: 1. **Define the Variables:** Let the length (L), breadth (B), and height (H) of the rectangular solid be represented in terms of a variable \( x \): - Length \( L = 5x \) - Breadth \( B = 4x \) - Height \( H = 2x \) 2. **Write the Formula for Total Surface Area:** The formula for the total surface area (TSA) of a rectangular solid is given by: \[ \text{TSA} = 2(LB + BH + HL) \] 3. **Substitute the Values:** Substitute \( L \), \( B \), and \( H \) into the TSA formula: \[ \text{TSA} = 2((5x)(4x) + (4x)(2x) + (2x)(5x)) \] Simplifying the terms inside the parentheses: - \( LB = 5x \cdot 4x = 20x^2 \) - \( BH = 4x \cdot 2x = 8x^2 \) - \( HL = 2x \cdot 5x = 10x^2 \) Therefore: \[ \text{TSA} = 2(20x^2 + 8x^2 + 10x^2) = 2(38x^2) = 76x^2 \] 4. **Set the TSA Equal to the Given Value:** We know from the problem that the total surface area is \( 1216 \, \text{cm}^2 \): \[ 76x^2 = 1216 \] 5. **Solve for \( x^2 \):** Divide both sides by 76: \[ x^2 = \frac{1216}{76} \] Simplifying this gives: \[ x^2 = 16 \] 6. **Find \( x \):** Taking the square root of both sides: \[ x = 4 \] 7. **Calculate the Dimensions:** Now substitute \( x \) back into the expressions for length, breadth, and height: - Length \( L = 5x = 5 \cdot 4 = 20 \, \text{cm} \) - Breadth \( B = 4x = 4 \cdot 4 = 16 \, \text{cm} \) - Height \( H = 2x = 2 \cdot 4 = 8 \, \text{cm} \) ### Final Answer: - Length = \( 20 \, \text{cm} \) - Breadth = \( 16 \, \text{cm} \) - Height = \( 8 \, \text{cm} \)
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Knowledge Check

  • The length and the breadth of a rectangular field are in the ratio 5:3. If the width of the field is 36 m, then its length is

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