Fill in the blanks by chossing the appropriate word/words from those given in the brackets: (increases, ionic radius, `CH_(2)`, same, sigma, ionic, 14, 2, decreases, 16, `CH_(3)`, pi, covalent, ionic)
An ______bond is formed when the electronegativity difference in teh combining atoms is more than ________

Answer

To solve the given question, we need to fill in the blanks with the appropriate words from the options provided.

The question states: "An ______ bond is formed when the electronegativity difference in the combining atoms is more than ______."

### Step 1: Identify the type of bond
We know that bonds can be classified based on the electronegativity difference between the atoms involved.
- If the electronegativity difference is high (generally greater than 1.7), the bond formed is typically an **ionic bond**.
- If the difference is low, the bond is usually covalent.

**Hint for Step 1:** Consider the general rule of thumb regarding electronegativity differences and the types of bonds they form.

### Step 2: Determine the threshold for ionic bond formation
From the information provided in the video transcript, it is mentioned that for an ionic bond to form, the electronegativity difference must be more than **2**. This is consistent with the common understanding that a difference greater than 1.7 typically indicates an ionic bond, but for this question, we will use the value of **2** as specified.

**Hint for Step 2:** Recall the common electronegativity difference values that indicate the formation of ionic bonds.

### Final Answer:
Filling in the blanks, we get:
"An **ionic** bond is formed when the electronegativity difference in the combining atoms is more than **2**."

### Summary of the Solution:
1. Identify the type of bond based on electronegativity difference.
2. Determine the threshold value for ionic bond formation.