Home
Class 12
MATHS
Let f(x)={x^3-x^2+10 x-5,xlt=1, \ -2x+(l...

Let `f(x)={x^3-x^2+10 x-5,xlt=1, \ -2x+(log)_2(b^2-2),x >1` Find the values of `b` for which `f(x)` has the greatest value at `x=1.`

A

`1ltble2`

B

`b={12}`

C

`b in(-oo,-1)`

D

`[-sqrt(130)-sqrt(2)]cup(sqrt(2),(sqrt(130))`

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MONOTONICITY MAXIMA AND MINIMA

    ARIHANT MATHS ENGLISH|Exercise Exercise (Single Option Correct Type Questions)|27 Videos
  • MONOTONICITY MAXIMA AND MINIMA

    ARIHANT MATHS ENGLISH|Exercise Exercise (More Than One Correct Option Type Questions)|16 Videos
  • MONOTONICITY MAXIMA AND MINIMA

    ARIHANT MATHS ENGLISH|Exercise Exercise For Session 4|15 Videos
  • MATRICES

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|49 Videos
  • PAIR OF STRAIGHT LINES

    ARIHANT MATHS ENGLISH|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|2 Videos

Similar Questions

Explore conceptually related problems

Let f(x)={{:(3x^2-2x+10, x lt 1),(-2,x gt 1):} The set of values of b for which f(x) has greatest value at x=1 is

"Let "f(x) ={underset(-2x + log_(2) (b^(2)-2), x gt1)(x^(3) -x^(2) +10 x-5 , x le 1). The set of values of b for which f(x) has greatest value at x= 1 is given by .

If f(x)=x^2+x+1 , then find the value of 'x' for which f(x-1) =f(x)

Let f(x) ={underset(x^(2) +xb " " x ge1)(3-x " "0le x lt1). Find the set of values of b such that f(x) has a local minima at x=1.

Iff(x)={3x^2+12 x-1,-1lt=xlt=2 37-x ,2

Ilf f(x)={x^3, x 2 , then find the value of f(-1)+f(1)+f(3) . Also find the value (s) of x for which f(x)=2.

let f(x)=-x^3+(b^3-b^2+b-1)/(b^2+3b+2) if x is 0 to 1 and f(x)=2x-3 if x if 1 to 3 .All possible real values of b such that f (x) has the smallest value at x=1 are

Let f(x)=(log(1+x/a)-log(1-x/b))/x ,x!=0. Find the value of f at x=0 so that f becomes continuous at x=0

If f(x)={{:(,ax^(2)-b,ale xlt 1),(,2,x=1),(,x+1,1 le xle2):} then the value of the pair (a,b) for which f(x) cannot be continuous at x=1, is

Find the least value of ' a ' such that the function f(x)=x^2+a x+1 is increasing on [1,\ 2] . Also, find the greatest value of ' a ' for which f(x) is decreasing on [1,\ 2] .