Home
Class 12
MATHS
If |z-i| ≤ 2 andz0 = 5+3i, the maximu...

If |z-i| ≤ 2 and`z_0 = 5+3i`, the maximum value of `|i z + z_0|` is

A

`5+sqrt13`

B

`5+sqrt2`

C

7

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the maximum value of \( |iz + z_0| \) given that \( |z - i| \leq 2 \) and \( z_0 = 5 + 3i \). ### Step-by-Step Solution: 1. **Understanding the Given Condition**: The condition \( |z - i| \leq 2 \) describes a circle in the complex plane centered at \( i \) (which is \( 0 + 1i \)) with a radius of 2. This means that \( z \) can take any value within or on the boundary of this circle. 2. **Expressing \( |iz + z_0| \)**: We need to find \( |iz + z_0| \). First, substitute \( z_0 \): \[ z_0 = 5 + 3i \] So, we have: \[ |iz + (5 + 3i)| = |iz + 5 + 3i| \] 3. **Rearranging the Expression**: We can rearrange the expression: \[ |iz + 5 + 3i| = |iz + (5 + 3i)| \] We can factor out \( i \): \[ = |i(z + 5i)| \] The modulus of a product is the product of the moduli: \[ = |i| \cdot |z + 5i| = 1 \cdot |z + 5i| = |z + 5i| \] 4. **Finding the Maximum of \( |z + 5i| \)**: Now, we need to maximize \( |z + 5i| \). Since \( z \) can be expressed as \( z = x + yi \) (where \( x \) and \( y \) are real numbers), we have: \[ |z + 5i| = |x + (y + 5)i| = \sqrt{x^2 + (y + 5)^2} \] 5. **Using the Circle Condition**: From the condition \( |z - i| \leq 2 \), we can express \( z \) as: \[ z = x + (y + 1)i \quad \text{where } \sqrt{x^2 + (y - 1)^2} \leq 2 \] This means that \( (x, y - 1) \) lies within or on the boundary of a circle centered at \( (0, 0) \) with radius 2. 6. **Finding the Center and Radius**: The center of the circle is at \( (0, 1) \) and the radius is 2. The maximum distance from the center \( (0, 1) \) to the point \( (0, 5) \) (which corresponds to \( z + 5i \)) is: \[ \text{Distance} = |(0, 5) - (0, 1)| = 4 \] 7. **Calculating Maximum Value**: Therefore, the maximum value of \( |z + 5i| \) occurs when \( z \) is at the point on the circle that is farthest from \( -5i \): \[ \text{Maximum value} = \text{Radius} + \text{Distance from center to } -5i = 2 + 4 = 6 \] ### Final Answer: Thus, the maximum value of \( |iz + z_0| \) is \( 7 \).
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • COMPLEX NUMBERS

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise EXERCISE-2 : ONE OR MORE THAN ONE ANSWER IS / ARE CORRECT|9 Videos
  • COMPLEX NUMBERS

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise EXERCISE-3:COMPREHENSION TYPE PROBLEMS|8 Videos
  • CIRCLE

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise Exercise - 5 : Subjective Type Problems|13 Videos
  • COMPOUND ANGLES

    VIKAS GUPTA (BLACK BOOK) ENGLISH|Exercise Exercise-5 : Subjective Type Problems|31 Videos

Similar Questions

Explore conceptually related problems

For a complex number Z, if |Z-i|le2 and Z_(1)=5+3i , then the maximum value of |iZ+Z_(1)| is (where, i^(2)=-1 )

if |z-2i| le sqrt2 , then the maximum value of |3+i(z-1)| is :

If |z|lt=4 , then find the maximum value of |i z+3-4i|dot

If |z-1|+|z+3|le8, then the maximum, value of |z-4| is =

If |z +2 - i |=5 then the maximum value of |3z+9-7i| is K, then find k

If z is any complex number satisfying |z-3-2i|lt=2 then the maximum value of |2z-6+5i| is

If arg ((z-6-3i)/(z-3-6i))=pi/4 , then maximum value of |z| :

If |z-2i|lesqrt(2), where i=sqrt(-1), then the maximum value of |3-i(z-1)|, is

If | (z - i)/(z + 2i)| = 1, |z| = 5/2 then the value of |z + 3i|

If | (z - i)/(z + 2i)| = 1, |z| = 5/2 then the value of |z + 3i|