Home
Class 11
PHYSICS
Two block A and B of masses 6 kg and 3 k...

Two block A and B of masses `6 kg` and `3 kg ` rest on a smooth horizontal surface as shown in figure If coefficient of friction between A and Bb is `0.4` the maximum horizontal force which can make them move without separation is

A

`72 N`

B

`40 N`

C

`36 N`

D

`20 N`

Text Solution

Verified by Experts

The correct Answer is:
c
Maximum friction force on block B is
`mu m_(B)g = 0.4 xx 3 xx 10 = 12N`
Hence, maximum acceleration `= (12)/(3) = 4ms^(-1)`
Hence , maximum force
`F = (m_(A) + m_(B)) a = (6 + 3) xx 4 = 36 N`
Afiber We can also apply the formula discussed in pervious problem by putting `mu_(2)= 0and mu_(1) = 0.4`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • NEWTON'S LAWS OF MOTION 2

    CENGAGE PHYSICS ENGLISH|Exercise Multiple Correct|2 Videos

  • NEWTON'S LAWS OF MOTION 2

    CENGAGE PHYSICS ENGLISH|Exercise Linked Comprehension|52 Videos

  • NEWTON'S LAWS OF MOTION 2

    CENGAGE PHYSICS ENGLISH|Exercise Subjective|21 Videos

  • NEWTON'S LAWS OF MOTION 1

    CENGAGE PHYSICS ENGLISH|Exercise Integer|5 Videos

  • PROPERTIES OF SOLIDS AND FLUIDS

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|2 Videos

Similar Questions

Explore conceptually related problems

Two block A and B of masses 5 kg. and 3 kg. respectively rest on smooth horizontal surface with B over A. The coefficient of friction between A and B. 0.5 the maximum horizontal force that can be applied to A so that there will be motion of A and B without separation is :-

On a smooth table two blocks of masses 2.5kg and 1.5kg are placed one over the other as shown in figure. If the coefficient of static friction between two blocks is 0.2, the maximum horizontal force to be applied on the lower block so that the two blocks move together is (g = ms^(-2) )

Knowledge Check

  • Two blocks A and B of masses 10 kg and 15 kg are placed in contact with each other rest on a rough horizontal surface as shown in the figure. The coefficient of friction between the blocks and surface is 0.2. A horizontal force of 200 N is applied to block A. The acceleration of the system is ("Take g"=10ms^(-2))

    A
    `4"ms"^(-2)`
    B
    `6"ms"^(-2)`
    C
    `8"ms"^(-2)`
    D
    `10"ms"^(-2)`

    • Similar Questions

    Explore conceptually related problems

    A block is kept on a rough horizontal surface as shown. Its mass is 2 kg and coefficient of friction between block and surface (mu)=0.5. A horizontal force F is acting on the block. When

    Two blocks of masses 4 kg and 6 kg are kept on a rough horizontal surface as shown. If the acceleration of 6 kg block is 5n , then n is :

    A block A of mass 2 kg is placed over smooth block B of mass 4 kg which is placed over a smooth horizontal floor The coefficient of friction between A and B is 0.4 when a horizontal forces of magnitude 10 N is applied on A the acceleration of block of A and B are

    Two block (A) 2kg and (B) 5kg rest one over the other on a smooth horizontal plane. The cofficient of static and dynamic friction between (A) and (B) is the sae and equal to 0.60. The maximum horizontal force that can be applied to (B) in order that both (A) and (B) do not have any relative motion:

    Two blocks A and B of respective masses 6 kg and 4 kg are connected with a string passing over a light friction less pulley as shown in the figure . The coefficient of friction between the block A and horizontal surface is 0.4 . Then the minimum mass of block C which should be placed over A to prevent it from moving is :

    A 3 kg block is placed over a 10 kg block and both are palced on a smooth horizontal surface. The coefficient of friction between the block is 0.2 . If a horizontal force of 20 N is applied to 3 kg block, accelerations of the two block in ms^(-2) are (take, g=ms^(-2) )

    Two blocks of masses 1 kg and 2 kg are placed in contact on a smooth horizontal surface as shown in fig. A horizontal force of 6N is applied d(a) on a 1-kg block. Find the force of interaction of the blocks. .

    Home
    Profile