Two soap bubbles A and B are kept in acl...

Two soap bubbles A and B are kept in aclosed chamber where the air is maintained at pressure `8 N/m^(2)`. The radiiof bubbles A and B are 2cm and 4 cm , respectively. Surface tension of the soap-water used to make bubbles is 0.04 N/m. The ratio of `n_(B)//n_(A)`is ( where `n_(A)` and `n_(B)` are the numbe of moles of air in bubbles A and B,respectively.)
[Neglect the effect of gravity]

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The correct Answer is:

`P_(A)=P_(0)+P_(A)=P_(0)+(4T)/R_(A)=16N//m^(2)`
`P_(B)=P_(0)+(4T)/R_(B)=12N//m^(2)`
`n_(B)//n_(A)=(P_(B))/(P_(A))((R_(B))/(R_(A)))^(3)=6`

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Two soap bubbles A and B are kept in a closed chamber where the air is maintained at pressure 8 N//m^(2) . The radii of bubbles A and B are 2 cm and 4 cm , respectively. Surface tension of the soap. Water used to make bubbles is 0.04 N//m . Find the ratio n_(B)//n_(A) , where n_(A) and n_(B) are the number of moles of air in bubbles A and B respectively. [Neglect the effect of gravity.]

bubbles A and B will be equal

bubbles A will be less than that in bubbles B

bubbles A will be greater than that in bubble B

bubbles A and B will be zero.