A ray of light undergoes deviation of `30^(@)` when incident on an equilateral prism of refractive index `sqrt(2)`. The angle made by the ray inside the prism with the base of the prism is

Explanation

For minimum deviation,
`mu=sin(A+(delta_(m))/(2))/(sin((A)/(2)))=("sin"((60+30)/2))/(sin(60/2))=(sin45^(@))/(sin30^(@))=sqrt(2)`
Since `mu=sqrt(2)` (given for the prism), the condition is for minimum deviation. In this case, the ray iniside the prism becomes parallel to the base. Therefore, the angle made by the ray inside the prism with the base of the prism is zero