An `alpha` particle and a proton are accelerated from rest by a potential difference of 100V. After this, their de-Broglie wavelengths are `lambda_a`
and `lambda_p` respectively. The ratio `(lambda_p)/(lambda_a)`, to the nearest integer, is.

Explanation

To solve the problem, we need to find the ratio of the de-Broglie wavelengths of a proton and an alpha particle after they have been accelerated through a potential difference of 100V.

### Step-by-Step Solution:

1. **Understand the de-Broglie wavelength formula**:
The de-Broglie wavelength (\( \lambda \)) is given by the formula:
\[
\lambda = \frac{h}{p}
...