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A colorimeter contains 400 g of water at...

A colorimeter contains `400 g` of water at a temperature of `5^(@)C`. Then, `200 g` of water at a temperature of `+10^(@)C` and `400 g` of ice at a temperature of `-60^(@)C` are added. What is the final temperature of the contents of calorimeter?
Specific heat capacity of water `-1000` cal`//kg//K`
Specific latent heat of fusion of ice `=80xx1000` cal`//kg`
Relative specific heat of ice `=0.5`

Text Solution

AI Generated Solution

To solve the problem, we will analyze the heat exchanges that occur when the different substances in the calorimeter come into thermal equilibrium. We have three components: water at 5°C, water at 10°C, and ice at -60°C. Our goal is to find the final temperature of the system. ### Step 1: Calculate the heat lost by the warm water The first component is `200 g` of water at `10°C`. When it cools down to `0°C`, the heat lost can be calculated using the formula: \[ Q_1 = m \cdot S \cdot \Delta T \] ...
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