The total number of electrons present in 18 mL of water (density of water is `1 g mL^(-1)` is:

Answer

A, B, C, D

Explanation

The total numbe of electrons present in `18 mL` of water is `6.023 xx 10^(24)`.
Number of electron in one molecules of `H_(2) O` is `2 + 8 = 10`
Denisty = 1
`18 mL` means `18 g`
Moles `= (18)/(18) = 1`
Moles `= 6.023 xx 10^(23)`
Electrons `= 6.023 xx 10^(23) xx 10 = 6.023 xx 10^(24)`