During a process, a system abdorbs `710J` of heat and does work. The change in `DeltaU` for the process is `460J`. What is the work done by the system?

Explanation

To solve the problem, we will use the First Law of Thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat absorbed (Q) by the system plus the work done (W) on or by the system. The equation can be expressed as:

\[ \Delta U = Q + W \]

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Heat absorbed by the system, \( Q = +710 \, \text{J} \) (since the system absorbs heat, it is positive).
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