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During a process, a system abdorbs 710J ...

During a process, a system abdorbs `710J` of heat and does work. The change in `DeltaU` for the process is `460J`. What is the work done by the system?

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To solve the problem, we will use the First Law of Thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat absorbed (Q) by the system plus the work done (W) on or by the system. The equation can be expressed as: \[ \Delta U = Q + W \] ### Step-by-Step Solution: 1. **Identify the Given Values:** - Heat absorbed by the system, \( Q = +710 \, \text{J} \) (since the system absorbs heat, it is positive). ...
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