Home
Class 11
CHEMISTRY
The enthalpy changes for the following r...

The enthalpy changes for the following reactions at `298k` and `1atm` are given below:
a. `CH_(3)COOH(l)+2O_(2)(g) rarr 2CO_(2)(g) +2H_(2)O(l),DeltaH =- 874 kJ`
b. `CH_(3)CH_(2)OH(l)+3O_(2)(g)rarr 2CO_(2)(g)+3H_(2)O(l),DeltaH =- 1363 kJ`
Calculate the internal enegry changes for these recaitons.

Text Solution

AI Generated Solution

To calculate the internal energy changes for the given reactions, we will use the relationship between enthalpy change (ΔH) and internal energy change (ΔU) given by the equation: \[ \Delta H = \Delta U + \Delta N_g RT \] Where: - ΔH = Enthalpy change ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMODYNAMICS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 6.3|27 Videos
  • THERMODYNAMICS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 6.4|16 Videos
  • THERMODYNAMICS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 6.1|26 Videos
  • STOICHIOMETRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|33 Videos

Similar Questions

Explore conceptually related problems

H_(2)(g)+(1)/(2)O_(2)(g)rarrH_(2)O(l), DeltaH =- 286 kJ 2H_(2)(g)+O_(2)(g)rarr2H_(2)O(l)……………kJ(+-?)

Calculate the enthalpy of formation of acetic acid from the following data. CH_(3)COOH(l)+2O_(2)(g)rarr 2CO_(2)(g)+2H_(2)O(l), " " Delta H=-207.9 k cal

CH_(4)(g) +2O_(2)(g) rarr CO_(2)(g) +2H_(2)O(l), DeltaH =- 890 kJ what is the calorific or fuel value of 1kg of CH_(4) ?

Find the heat of formation of ethyl alcohol for following data C(s) +O_(2)(g) rarr CO_(2)(g) DeltaH =- 94 kcal H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l), DeltaH =- 68 kcal C_(2)H_(5)OH(l)+3O_(2)(g) rarr 2CO_(2)(g) +3H_(2)O(l) DeltaH =- 327 kcal

C_(4)H_(10)+(13)/(2)O_(2)(g)rarr4CO_(2)(g)+5H_(2)O(l), DeltaH =- 2878 kJ DeltaH is the heat of……….of butane gas.

The enthalpies for the following reactions (DeltaH^(Theta)) at 25^(@)C are given below. a. (1)/(2)H_(2)(g) +(1)/(2)O_(2)(g) rarr OH(g) DeltaH = 10.06 kcal b. H_(2)(g) rarr 2H(g), DeltaH = 104.18 kcal c. O_(2)(g) rarr 2O(g), DeltaH = 118.32 kcal Calculate the O-H bond energy in the hydroxyl radical.

Given that : C(s)+O_(2)(g)to CO_(2)(g) , Delta H = -394 kJ and 2H_(2)(g)+O_(2)(g)to 2H_(2)O(l) , Delta H =- 568 kJ and C_(2)H_(5)OH(l)+3O_(2)(g)to 2CO_(2)(g)+3H_(2)O(l) , Delta H =- 1058 kJ/mole. Using the data, the heat of formation of ethanol is

Compounds with carbon-carbon double bond, such as ethylene, C_(2)H_(4) , add hydrogen in a reaction called hydrogenation. C_(2)H_(4)(g)+H_(2)(g) rarr C_(2)H_(6)(g) Calculate enthalpy change for the reaction, using the following combustion data C_(2)H_(4)(g) + 3O_(2)(g) rarr 2CO_(2)(g) + 2H_(2)O(g) , Delta_("comb")H^(Θ) = -1401 kJ mol^(-1) C_(2)H_(6)(g) + 7//2O_(2)(g)rarr 2CO_(2) (g) + 3H_(2)O(l) , Delta_("comb")H^(Θ) = -1550kJ H_(2)(g) + 1//2O_(2)(g) rarr H_(2)O(l) , Delta_("comb")H^(Θ) = -286.0 kJ mol^(-1)

For the reaction : C_(2)H_(5)OH(l)+3O_(2)(g)rarr2CO_(2)(g)+3H_(2)O(g) if Delta U^(@)= -1373 kJ mol^(-1) at 298 K . Calculate Delta H^(@)

The enthalpy changes for two reactions are given by the equations: 2Cr(s) +(3)/(2)O_(2)(g) rarr Cr_(2)O_(3)(s), DeltaH^(Theta) =- 1130 kJ C(s) +(1)/(2)O_(2)(g)rarr CO(g), DeltaH^(Theta) =- 110 kJ What is the enthalpy change in kJ for the following reactions? 3C(s) +Cr_(2)O_(3)(s) rarr 2Cr(s) +3CO(g)