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An element E loses one alpha and two bet...

An element E loses one `alpha` and two `beta`-particles in three successive stages. The resulting element will be

A

An isobar of `X`

B

An isotope of `X`

C

`X` itself

D

An isotone of `X`

Text Solution

Verified by Experts

The correct Answer is:
B
Let the reaction is
`._(Z)X^(A) overset(-alpha)rarr ._(Z-2)A^(A-4)overset(-beta)rarr ._(Z-1)B^(a-4) overset(-beta)rarr ._(Z)C^(A-4)`
Therefore, `X` and `C` are isotope `i.e.,` same atomic number.
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