The `n//p` ratio for a stable lighter nuclei is about `………………` .

Answer

To solve the question regarding the n/p (neutrons to protons) ratio for stable lighter nuclei, we can follow these steps:

### Step 1: Understand the n/p Ratio
The n/p ratio is defined as the ratio of the number of neutrons (n) to the number of protons (p) in a nucleus. This ratio helps us understand the stability of a nucleus.

### Step 2: Identify Stable Lighter Nuclei
Stable lighter nuclei typically refer to those with low atomic numbers. Examples include elements like hydrogen, helium, lithium, beryllium, boron, carbon, nitrogen, and oxygen.

### Step 3: Calculate n/p Ratio for a Stable Lighter Nucleus
Let's take the example of nitrogen-14 (N-14) to illustrate the calculation:
- **Mass Number (A)** of nitrogen-14 = 14
- **Atomic Number (Z)** of nitrogen = 7 (which indicates the number of protons)

Using the formula:
\[ \text{Number of Neutrons (n)} = \text{Mass Number (A)} - \text{Atomic Number (Z)} \]
\[ n = 14 - 7 = 7 \]

Now, we can calculate the n/p ratio:
\[ \text{n/p ratio} = \frac{n}{p} = \frac{7}{7} = 1 \]

### Step 4: Confirm with Another Example
We can also check another stable lighter nucleus, such as carbon-12 (C-12):
- **Mass Number (A)** of carbon-12 = 12
- **Atomic Number (Z)** of carbon = 6

Calculating the number of neutrons:
\[ n = 12 - 6 = 6 \]

Now, calculating the n/p ratio:
\[ \text{n/p ratio} = \frac{n}{p} = \frac{6}{6} = 1 \]

### Conclusion
From the calculations above, we can conclude that the n/p ratio for stable lighter nuclei is approximately 1.

### Final Answer
The n/p ratio for a stable lighter nucleus is about **1**.

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