An element `._(Z)M^(A)` undergoes an `alpha-` emission followed by two successive `beta-` emissions. The element formed is `………………………..` .

Explanation

To solve the problem, we will follow the steps of the nuclear transformations that the element undergoes.

### Step 1: Initial Element
We start with the element represented as \( _{Z}M^{A} \), where \( A \) is the mass number and \( Z \) is the atomic number.

### Step 2: Alpha Emission
When the element undergoes alpha emission, it loses an alpha particle, which has a mass number of 4 and an atomic number of 2. The equation for this transformation can be written as:
\[
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