The shape of a moleculs is determined by electron pair repulsions in the valence shell A.lp occupies a larger space than a bp because it is not shared by two nuclei The the lp lp repulsion is greater than the lp-bp repulsion, which in trun is greater the bp-bp repulsion. The presence of lp causes distortion of bond angles hence, a daviation from an ideal shape THe extent of distortion depends upon the orientation of the lp's around the central atom In a trigonal bipyramid, the lp's occupy equatorial positions than the apical ones In `AB_(n)` type molecules, as the `EN` of A increases, the bp's come closer and the repulsion between them increases. On the other hand, as `EN` of `B` increases, the lp s get farther and repulsion decreases
The shape of which of the following molecules will not be distored ?

Options

A. `BrF_(3)`
B. `ClF_(3)`
C. `XeF_(4)`
D. `XeF_(6)`

Explanation

To determine the shape of a molecule that will not be distorted due to lone pair and bond pair repulsions, we need to analyze the given molecules based on their electron pair geometry and the presence of lone pairs.

### Step-by-Step Solution:

1. **Understanding Electron Pair Geometry**:
- The shape of a molecule is influenced by the repulsion between electron pairs in the valence shell. Lone pairs (lp) occupy more space than bond pairs (bp) because they are not shared between two nuclei.
- The order of repulsion strength is: lp-lp > lp-bp > bp-bp.

2. **Identifying the Molecules**:
- We need to evaluate the following molecules: BrF3, ClF3, XeF4, and XeF6.

3. **Analyzing BrF3 and ClF3**:
- For both BrF3 and ClF3:
- Total electron pairs = 2 lone pairs + 3 bond pairs = 5 pairs.
- Hybridization = sp3d.
- Geometry = trigonal bipyramidal.
- The presence of 2 lone pairs will cause distortion due to lp-bp repulsion.
- **Conclusion**: Both BrF3 and ClF3 will have distorted shapes.

4. **Analyzing XeF4**:
- For XeF4:
- Total electron pairs = 2 lone pairs + 4 bond pairs = 6 pairs.
- Hybridization = sp3d2.
- Geometry = octahedral or square planar.
- The lone pairs are positioned opposite each other, leading to equal repulsion on both sides, resulting in no distortion.
- **Conclusion**: XeF4 will not be distorted.

5. **Analyzing XeF6**:
- For XeF6:
- Total electron pairs = 1 lone pair + 6 bond pairs = 7 pairs.
- Hybridization = sp3d3.
- Geometry = distorted octahedral.
- The presence of a lone pair will cause distortion.
- **Conclusion**: XeF6 will have a distorted shape.

6. **Final Conclusion**:
- Among the given molecules, only **XeF4** will have a shape that is not distorted.