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5.0 cm^(3) of H(2)O(2) liberates 0.508 g...

`5.0 cm^(3)` of `H_(2)O_(2)` liberates 0.508 g of iodine from an acidified KI solution. The strength of `H_(2)O_(2)` solution in terms of volume strenth at STP is

Text Solution

Verified by Experts

`mEq of I_(2)=0.508/127xx1000`
`mEq of KI=0.508/127xx1000`
`mEq of H_(2)O_(2)=0.508/127xx1000`
Normality of `H_(2)O_(2)=0.503/127xx1000/5`
For `H_(2)O_(2)`
`5.6xx` Normality =Volume strength
`:.` Volume strength =`5.6xx(0.508xx1000)/(127xx5)`
`=4.48 V`
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Knowledge Check

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