The oxide that gives H(2)O(2) on treatme...

The oxide that gives `H_(2)O_(2)` on treatment with a dilute sulfuric acid is

`PbO_2`

`Na_2 O_2`

`MnO_2`

`TiO_2`

Text Solution

Verified by Experts

The correct Answer is:

Only true peroxides which have `O-O-bond` give hydrogen perxide with dilute acids.
`Na_(2) O_(2) + H_(2) SO_(4) rarr Na_(2) SO_(4) + H_(2) O_(2)`
Note :
(i) But peroxide with conc. Acids leberates `H_(2) O_(2)` and `O_(2)`, e.g.
`BaO_(2) + H_(2) SO_(4) (dil.) rarr BaSO_(4) + H_(2) O_(2)`
`BaO_(2) + 2H_(2) SO_(4) (conc.) rarrr 2 BaSO_(4) + 2 H_(2) O_(2) + O_(2)`
(ii) Superoxides (e.g., `KO_(2), RbO_(2), CsO_(2))` react with water to give `H_(2) O_(2)` and `O_(2)`.
`2 KO_(2) + 2H_(2) O rarr 2 KOH + H_(2) O_(2) + O_(2)`.

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The oxide that give H_(2)O_(2) on treatment with dilute H_(2)SO_(4) is

`PbO_(2)`

`BaO_(2).8H_(2)O`

`MnO_(2)`

`TiO_(2)`

Propanal on treatment with dilute sodium hydroxide gives

`CH_(3)CH_(2)CH_(2)CH_(2)CH_(2)CHO`

`CH_(3)CH_(2)CH(OH)CH_(2)CH_(2)CHO`

`CH_(3)CH_(2)CH(OH)CH(CH_(3))CHO`

`CH_(3)CH_(2)COOH`

An ore gives CO_2 on being treated with dilute hydrochloric acid. Which process should be used to convert this ore into oxide?

Calcination

Roasting

Froth floatation

Sedimentation