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Yellow coloured solution of FeCl(3) cha...

Yellow coloured solution of `FeCl_(3)` changes in light green when

A

`SnCl_(2)` is added

B

`Zn` is added

C

`H_(2)S` gas is added

D

All true

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AI Generated Solution

The correct Answer is:
To solve the question regarding the yellow colored solution of `FeCl3` changing to light green, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Initial State**: - The yellow colored solution is due to the presence of ferric ions (Fe³⁺) in `FeCl3`. 2. **Identify the Target State**: - The light green color corresponds to ferrous ions (Fe²⁺) in `FeCl2`. 3. **Understand the Chemical Change**: - The change from yellow to light green indicates a reduction process where Fe³⁺ is being reduced to Fe²⁺. 4. **Identify Reducing Agents**: - To reduce Fe³⁺ to Fe²⁺, a reducing agent is required. The options provided are: - SnCl₂ (Stannous chloride) - Zn (Zinc) - H₂S (Hydrogen sulfide) 5. **Evaluate Each Option**: - **SnCl₂**: This is a known reducing agent that can reduce Fe³⁺ to Fe²⁺. - **Zn**: Zinc is also a reducing agent and can facilitate the reduction of Fe³⁺ to Fe²⁺. - **H₂S**: Hydrogen sulfide can act as a reducing agent and can reduce Fe³⁺ to Fe²⁺ as well. 6. **Conclusion**: - Since all three substances (SnCl₂, Zn, H₂S) can act as reducing agents to convert Fe³⁺ to Fe²⁺, the correct answer is that the yellow solution of `FeCl3` changes to light green when any of these reducing agents are added. ### Final Answer: - The yellow colored solution of `FeCl3` changes to light green when SnCl₂, Zn, or H₂S is added. Therefore, the correct option is **all are true**. ---
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Knowledge Check

  • The aqueous solution of FeCl_3 is

    A
    acidic
    B
    alkaline
    C
    neutral
    D
    either acidic or basic depending upon concentration.
  • Yellow coloured aquesous solution of sodium chromate changes to orange when acidified with sulphuric acid because

    A
    `H^(+)` ions convert chromate ions to dichromate ions
    B
    `H^(+)` ions react with sodium chromate to give sodium ions which turn solution orange
    C
    `Cr^(3+)` ions are liberated in the solution which turn the solution orange
    D
    sodium hydroxide is formed during the reaction which imparts orange colour to the solution.
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