An alcohol A, when heated with conc. `H_(2)SO_(4)` gives an alkene B. When B is bubbled through bromine water and the product obtained is dehydrohalogenated with exccess of sodamide, a new compound C is obtained. The compound C gives D when treated with warm dilute `H_(2)SO_(4)` in the presence of `HgSO_(4)`. D can also be obtained either byh oxidising A with `KMnO_(4)` or form acetic acid through its calcium salt. Identify A, B, C, and D.

Explanation

To solve the problem, we need to identify the compounds A, B, C, and D based on the reactions described. Let's break it down step by step:

### Step 1: Identify Alcohol A
The problem states that an alcohol A, when heated with concentrated sulfuric acid, gives an alkene B. This indicates that A is likely a secondary alcohol, as secondary alcohols typically undergo dehydration to form alkenes.

**Conclusion:** Alcohol A is 2-propanol (isopropyl alcohol).

### Step 2: Identify Alkene B
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