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Avogadro's law states that under similar...

Avogadro's law states that under similar condition of T and P, equal number of particles. Experiments show that at one atmosphere pressure and at a temperature 273 K (i.e. at STP) one mole of any gas occupy a volume approximately 22.4 litre. Therefore number of moles of any sample of gas can be found by comparing its volume at STP with 22.4. 1 mole of any species contains `6.023xx10^(23)` particles which is denoted by symbol `N_(A)`. Number of atoms present in 1 gm-atom of an element or number of molecules present in 1 gm-molecule of any substance is equal to `N_(A)`. Hence it is number of particles present in one mole of the substance.
If `N_(AV)` is Avogardo's number, then 10 amu will be equal to _________ gram.

A

`10 N_(AV)`

B

`(N_(AV))/(10)`

C

`(10)/(N_(AV))`

D

`N_(AV)`

Text Solution

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The correct Answer is:
To solve the question "If \( N_A \) is Avogadro's number, then 10 amu will be equal to _________ grams," we will follow these steps: ### Step 1: Understand the definition of 1 amu 1 amu (atomic mass unit) is defined as \( \frac{1}{12} \) of the mass of a carbon-12 atom. This means that the mass of 1 amu can be expressed in grams as: \[ 1 \text{ amu} = \frac{1}{12} \times \text{mass of carbon-12 in grams} \] Since the mass of 1 mole of carbon-12 is 12 grams, we can write: \[ 1 \text{ amu} = \frac{12 \text{ grams}}{N_A} \] where \( N_A \) is Avogadro's number, approximately \( 6.022 \times 10^{23} \) particles/mole. ### Step 2: Calculate the mass of 10 amu To find the mass of 10 amu, we multiply the mass of 1 amu by 10: \[ 10 \text{ amu} = 10 \times \left(\frac{12 \text{ grams}}{N_A}\right) = \frac{10 \times 12 \text{ grams}}{N_A} \] This simplifies to: \[ 10 \text{ amu} = \frac{120 \text{ grams}}{N_A} \] ### Final Answer Thus, 10 amu is equal to: \[ \frac{120}{N_A} \text{ grams} \]
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Avogadro's lasw states that under conditions of constant temp. and pressure equal volume of gases contain equal no. of particles. Experimental investigation shows that at one atmosphere pressure and a temperature of 273 k, one mole of any gas occupies a volume of which is very close to 22.4 lit. Therefore, the number of moles in any gas sample canbe found by comparing its volume at STP with 22.4 lit. At STP 40 lit of CO_(2) contains

Avogadro's lasw states that under conditions of constant temp. and pressure equal volume of gases contain equal no. of particles. Experimental investigation shows that at one atmosphere pressure and a temperature of 273 k, one mole of any gas occupies a volume of which is very close to 22.4 lit. Therefore, the number of moles in any gas sample canbe found by comparing its volume at STP with 22.4 lit. Number of gram atoms of oxygen present in 0.3 gram mole of H_(2)C_(2)O_(4).2H_(2)O is

Knowledge Check

  • For an ideal gas, number of moles per litre in terms of its pressure P, gas constant R and temperature T is

    A
    PT / R
    B
    P / RT
    C
    PRT
    D
    RT / P
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