The weight of 1 mole of a gas of density `0.1784gL^(-)` at NTP is?

Answer

To find the weight of 1 mole of a gas with a given density at NTP (Normal Temperature and Pressure), we can follow these steps:

### Step 1: Understand the relationship between mass, volume, and density
The formula to calculate mass (m) is given by:
\[ m = \text{density} \times \text{volume} \]

### Step 2: Identify the volume of 1 mole of gas at NTP
At NTP, 1 mole of any ideal gas occupies a volume of:
\[ 22.4 \, \text{L} \]

### Step 3: Use the given density
The density of the gas is provided as:
\[ 0.1784 \, \text{g/L} \]

### Step 4: Calculate the mass of the gas
Now, we can substitute the values into the mass formula:
\[ m = \text{density} \times \text{volume} \]
\[ m = 0.1784 \, \text{g/L} \times 22.4 \, \text{L} \]

### Step 5: Perform the calculation
Calculating the above expression:
\[ m = 0.1784 \times 22.4 = 3.99376 \, \text{g} \]

### Step 6: Round the result
Rounding this to two decimal places, we get:
\[ m \approx 4.00 \, \text{g} \]

### Final Answer
The weight of 1 mole of the gas is approximately:
\[ \text{Weight} = 4 \, \text{g} \]

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