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The equation of the parabola with vertex...

The equation of the parabola with vertex at (0, 0) and focus at (0, 4) is

A

`y^(2) =16x`

B

`x^(2) = 16y`

C

`x^(2) = 4y`

D

`y^(2) = 4x`

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the parabola with a vertex at (0, 0) and a focus at (0, 4), we can follow these steps: ### Step 1: Identify the vertex and focus The vertex of the parabola is given as (0, 0) and the focus is at (0, 4). ### Step 2: Determine the orientation of the parabola Since the focus is above the vertex (0, 0), the parabola opens upwards. ### Step 3: Use the standard form of the equation of a parabola The standard form of the equation of a parabola that opens upwards is given by: \[ x^2 = 4ay \] where \( a \) is the distance from the vertex to the focus. ### Step 4: Calculate the value of \( a \) The distance \( a \) can be calculated as the distance from the vertex (0, 0) to the focus (0, 4): \[ a = 4 \] ### Step 5: Substitute \( a \) into the standard equation Now, substituting \( a = 4 \) into the standard equation: \[ x^2 = 4(4)y \] \[ x^2 = 16y \] ### Step 6: Write the final equation Thus, the equation of the parabola is: \[ x^2 = 16y \] ### Conclusion The equation of the parabola with vertex at (0, 0) and focus at (0, 4) is: \[ x^2 = 16y \] ---
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