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In DeltaABC if (sinA)/(sinC)=(sin(A-B))...

In `DeltaABC` if `(sinA)/(sinC)=(sin(A-B))/(sin(B-C))`, then `a^(2), b^(2), c^(2)` are in :

A

a,b,c are in A.P.

B

`a^(2), b^(2),c^(2)` are in A.P.

C

a,b,c are in H.P.

D

`a^(2), b^(2), c^(2)` are in H.P.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we start with the given equation in triangle \( \Delta ABC \): \[ \frac{\sin A}{\sin C} = \frac{\sin(A - B)}{\sin(B - C) \] ### Step 1: Rewrite Angles Using the property of angles in a triangle, we know that \( A + B + C = \pi \). Therefore, we can express \( A \) and \( C \) in terms of \( B \): \[ A = \pi - (B + C) \quad \text{and} \quad C = \pi - (A + B) \] ### Step 2: Substitute into Sine Functions Now, we can substitute these into the sine functions: \[ \sin A = \sin(\pi - (B + C)) = \sin(B + C) \] \[ \sin C = \sin(\pi - (A + B)) = \sin(A + B) \] ### Step 3: Substitute into the Given Equation Substituting these into the original equation gives us: \[ \frac{\sin(B + C)}{\sin(A + B)} = \frac{\sin(A - B)}{\sin(B - C)} \] ### Step 4: Cross Multiply Cross-multiplying yields: \[ \sin(B + C) \cdot \sin(B - C) = \sin(A - B) \cdot \sin(A + B) \] ### Step 5: Use Sine Addition and Subtraction Formulas Using the sine addition and subtraction formulas, we can expand both sides: \[ \sin(B + C) = \sin B \cos C + \cos B \sin C \] \[ \sin(B - C) = \sin B \cos C - \cos B \sin C \] \[ \sin(A - B) = \sin A \cos B - \cos A \sin B \] \[ \sin(A + B) = \sin A \cos B + \cos A \sin B \] ### Step 6: Set Up the Equation Substituting these expansions into our equation gives: \[ (\sin B \cos C + \cos B \sin C)(\sin B \cos C - \cos B \sin C) = (\sin A \cos B - \cos A \sin B)(\sin A \cos B + \cos A \sin B) \] ### Step 7: Simplify Using Product-to-Sum Identities Using product-to-sum identities, we can simplify both sides. After simplification, we will find a relation involving \( \sin^2 A, \sin^2 B, \sin^2 C \). ### Step 8: Establish the Relationship From the derived equation, we can conclude that: \[ 2 \sin^2 B = \sin^2 A + \sin^2 C \] This implies that \( \sin^2 A, \sin^2 B, \sin^2 C \) are in arithmetic progression (AP). ### Step 9: Apply Sine Rule Using the sine rule, we know: \[ \frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} \] If \( \sin^2 A, \sin^2 B, \sin^2 C \) are in AP, then \( a^2, b^2, c^2 \) must also be in AP. ### Conclusion Thus, we conclude that \( a^2, b^2, c^2 \) are in arithmetic progression (AP). ### Final Answer The answer is that \( a^2, b^2, c^2 \) are in AP. ---
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