Write balanced chemical equation for reaction of slaked lime with chlorine.

Answer

To write the balanced chemical equation for the reaction of slaked lime with chlorine, we will follow these steps:

### Step 1: Identify the Reactants
Slaked lime is chemically represented as \( \text{Ca(OH)}_2 \). The other reactant is chlorine, represented as \( \text{Cl}_2 \).

### Step 2: Identify the Products
When slaked lime reacts with chlorine, the products formed are:
- Calcium chloride, represented as \( \text{CaCl}_2 \)
- Bleaching powder, represented as \( \text{Ca(OCl)_2} \)
- Water, represented as \( \text{H}_2\text{O} \)

### Step 3: Write the Unbalanced Equation
The unbalanced chemical equation can be written as:
\[ \text{Ca(OH)}_2 + \text{Cl}_2 \rightarrow \text{CaCl}_2 + \text{Ca(OCl)}_2 + \text{H}_2\text{O} \]

### Step 4: Balance the Equation
To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides.

1. **Calcium (Ca)**: There are 2 calcium atoms on the product side (1 in \( \text{CaCl}_2 \) and 1 in \( \text{Ca(OCl)_2} \)), so we need 2 \( \text{Ca(OH)}_2 \) on the reactant side.
2. **Chlorine (Cl)**: There are 4 chlorine atoms in total on the product side (2 in \( \text{CaCl}_2 \) and 2 in \( \text{Ca(OCl)_2} \)), so we need 2 \( \text{Cl}_2 \) on the reactant side.
3. **Hydrogen (H)**: There are 4 hydrogen atoms on the product side (2 in \( \text{H}_2\text{O} \)), so we need 2 \( \text{H}_2\text{O} \) on the product side.

The balanced equation is:
\[ 2 \text{Ca(OH)}_2 + 2 \text{Cl}_2 \rightarrow 2 \text{CaCl}_2 + \text{Ca(OCl)}_2 + 2 \text{H}_2\text{O} \]

### Final Balanced Equation
The final balanced chemical equation for the reaction of slaked lime with chlorine is:
\[ 2 \text{Ca(OH)}_2 + 2 \text{Cl}_2 \rightarrow 2 \text{CaCl}_2 + \text{Ca(OCl)}_2 + 2 \text{H}_2\text{O} \]

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