Oxidation state exhibited by Cl in `HClO_(3)` is

Answer

To determine the oxidation state of chlorine (Cl) in the compound HClO₃ (chloric acid), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the known oxidation states**:
- The oxidation state of hydrogen (H) is +1.
- The oxidation state of oxygen (O) is -2.

2. **Set up the equation**:
- In HClO₃, we have one hydrogen atom, one chlorine atom, and three oxygen atoms.
- Let the oxidation state of chlorine be represented as \( x \).
- The overall charge of the molecule is neutral (0).

3. **Write the equation based on the oxidation states**:
- The contribution from hydrogen is +1.
- The contribution from three oxygen atoms is \( 3 \times (-2) = -6 \).
- Therefore, the equation can be set up as:
\[ +1 + x + (-6) = 0 \]

4. **Simplify the equation**:
- This simplifies to:
\[ +1 + x - 6 = 0 \]
- Rearranging gives:
\[ x - 5 = 0 \]

5. **Solve for \( x \)**:
- Adding 5 to both sides results in:
\[ x = +5 \]

6. **Conclusion**:
- The oxidation state of chlorine (Cl) in HClO₃ is +5.

### Final Answer:
The oxidation state exhibited by Cl in HClO₃ is +5.