Home
Class 11
CHEMISTRY
Na and Mg crystallize in bcc- and fcc-ty...

`Na` and `Mg` crystallize in bcc- and fcc-type crystals, respectively, then the number of atoms of `Na` and `Mg` present in the unit cell of their respective crystal is

A

4 and 2

B

9 and 14

C

14 and 9

D

2 and 4

Text Solution

Verified by Experts

The correct Answer is:
D
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLID STATE

    RESONANCE ENGLISH|Exercise Exercise -3 (JEE -MAIN)|12 Videos

  • SOLID STATE

    RESONANCE ENGLISH|Exercise APSP|29 Videos

  • SOLID STATE

    RESONANCE ENGLISH|Exercise Exercise -3 (Part-I)|16 Videos

  • S BLOCK ELEMENTS

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Biomolecules & Polymer)|4 Videos

  • STRUCTURAL IDENTIFICATION & PRACTICAL ORGANIC CHEMISTRY

    RESONANCE ENGLISH|Exercise Section -B|18 Videos

Similar Questions

Explore conceptually related problems

Na and Mg crystallize in bcc- and fcc-type crystals, the ratio of number of atoms present in the unit cell of their respective crystal is

Na and Mg crystallize in bcc- and fcc-type crystals, the ratio of number of atoms present in the unit cell of their respective crystal is

Knowledge Check

  • Na and Mg crystallise in bcc and foc structures respectively. The value of Z (number of atoms) for their crystals is:

    A
    8 and 14
    B
    2 and 4
    C
    14 and 8
    D
    6 and 4

    • Similar Questions

    Explore conceptually related problems

    On the basis of unit cell concept a crystal has :

    The ratio of atoms present per unit cell in bcc to that present in fcc is

    For a crystal of diamond, state : The number of carbon atoms present per unit cell.

    If the number of atoms per unit in a crystal is 2, the structure of crystal is:

    The number of NaCl molecules in unit cell of its crystal is

    How many atoms constitute one unit cell of simple cubic crystal?

    How manu atoms are present in the unit cell of : (i) Simple cubic (ii) bcc (iii) fcc.

    Home
    Profile