An AC of frequency f is flowing in a circuit containing a resistance R and capacitance C in series. The impedance of the circuit is equal to
An alternating emf of 110 V is applied to a circuit containing a resistance R of 80 Omega and an inductor L in series. The current is found to lag behind the supply voltage by an angle theta=tan^(1) (3//4) . Find the : If the inductor has a coefficient of self inductance of 0.1 H, what is the frequency of the applied emf ?
An alternating emf of 110 V is applied to a circuit containing a resistance R of 80 Omega and an inductor L in series. The current is found to lag behind the supply voltage by an angle theta=tan^(1) (3//4) . Find the : Current flowing in the circuit
An alternating emf of 110 V is applied to a circuit containing a resistance R of 80 Omega and an inductor L in series. The current is found to lag behind the supply voltage by an angle theta=tan^^(1) (3//4) . Find the : Impedance of the circuit
An alternating emf of 110 V is applied to a circuit containing a resistance R of 80 Omega and an inductor L in series. The current is found to lag behind the supply voltage by an angle theta=tan^(1) (3//4) . Find the : Inductive reactance
In an alternating current circuit in which an inductance and capacitance are joined in series, current is found to be maximum when the value of inductance is 0.5 henry and the value of capacitance is 8µF. The angular frequency of applied alternating voltage will be
An inductive circuit contains a resistance of 10 ohms and an inductance of 2 henry. If an alternating voltage of 120 V and frequency 60 Hz is applied to this circuit, the current in the circuit would be nearly
An inductor of inductance L and ressistor of resistance R are joined in series and connected by a source of frequency omega . Power dissipated in the circuit is
An a.c. source of angular frequency omega is fed across a resistor R and a capacitor C in series. The current registered is I. If now the frequency of the source is changed to omega//3 (but maintaining the same voltage), the current in the circuit is found to be halved. calculate the ratio of reactance to resistance at the original frequency omega .
An ac source of angular frequency omega is fed across a resistor R and a capacitor C in series. The current registered is I. If now the freqency of source is chaged to (omega)//3 (but maintainging the same voltage), the current in the circuit is found to be halved. Calculate the ration of hte reactance to resistance at the original frequency omega .
