Home
Class 12
PHYSICS
A coil has an inductance of 22/pi H and ...

A coil has an inductance of `22/pi H` and is joined in series with a resistance of `220 Omega`.When an alternating `e.m.f` of `220 V` at `50 c.p.s` is applied to it.then the wattless component of the `rms` current in the circuit is

A

5ampere

B

0.5ampere

C

0.7ampere

D

7ampere

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise EXERCISE-3|1 Videos

  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise EXERCISE-4|1 Videos

  • ALTERNATING CURRENT

    RESONANCE ENGLISH|Exercise PART-III: Match the column|2 Videos

  • ATOMIC PHYSICS

    RESONANCE ENGLISH|Exercise Advanved level problems|17 Videos

Similar Questions

Explore conceptually related problems

A coil has a inductance of 0.7pi H and is joined in series with a resistance of 220 Omega . When an alternating emf of 220V at 50 cps is applied to it, then the watt-less component of the current in the circuit is (take 0.7pi = 2.2)

A coil has inductance of (11)/(5pi)H and is joined in series with a resistance of 220Omega . When an alternating emf of 220V at 50Hz is applied to it, then the wattless component of the current in the circuit is

Knowledge Check

  • A circuit consists of a resistance 10 ohm and a capacitance of 0.1 mu F If an alternating e.m.f. of 100 V. 50 Hz is applied, calculate the current in the circuit.

    A
    `3.14 mA`
    B
    `6.28 mA`
    C
    `1.51 mA`
    D
    `7.36 mA`

  • An alternating supply of 220 V is applied across a circuit with resistance 22 Omega and impedance 44 Omega . The power dissipated in the circuit is

    A
    1100 W
    B
    550 W
    C
    2200 W
    D
    (2200/3) W

    • Similar Questions

    Explore conceptually related problems

    An alternating emf given by equation e=300sin(100pi)t V is applied to a resistance 100 Omega . The rms current through the circuit is (in amperes).

    A coil of 40 H inductance is connected in series with a resistance of 8 ohm and the combination is joined to the terminals of a 2 V battery. The time constant of the circuit

    In an ac circuit , L = (0.4)/(pi) H and R = 30 Omega . If the circuit has an alternating emf of 200 V, 50 cps, the impedance and the current in the circuit will be :

    A coil of inductance 0.20 H is connected in series with a switch and a cell of emf 1.6 V . The total resistance of the circuit is 4.0 Omega . What is the initial rate of growth of the current when the switch is closed?

    A choke coil of resistance 5 Omega and inductance 0.6 H is in series with a capacitance of 10 (mu)F . If a voltage of 200 V is applied and the frequency is adjusted to resonance, the current and voltage across the inductance and capacitance are (I_0), (V_0) and (V_1) respectively. we have

    A coil having a resistance of 50.0 Omega and an inductance of 0.500 henry is connected to an AC source of 110 volts, 50.0 cycle/s. Find the rms value of the current in the circuit.

    Home
    Profile