An `ac` voltage source `V=V_(0) sin omega t` is connected across a resistance `R` and capacitance `C` as shown in figure.It is given that `R=1/(omegaC)`.The peak current is `I_(0)`. If the angular frequency of the voltage source is changed to `omega/sqrt3` keeping `R` and `C` fixed, then the new peak current in the circuit in the circuit is:
An AC voltage source V=V_0siomegat is connected across resistance R and capacitance C as shown in figureure. It is given that R=1/omegaC . The peak current is I_0 . If the angular frequency of the voltage source is changed to omega/sqrt3, then the new peak current in the circuit is .
An AC voltage source V=V_0sinomegat is connected across resistance R and capacitance C as shown in figure. It is given that omegaC=1/R . The peak current is I_0 . If the angular frequency of the voltage source is changed to omega/sqrt3, then the new peak current in the circuit is .
An ac source of voltage V=V_(m)sin omega t is connected across the resistance R as shown in figure. The phase relation between current and voltage for this circuit is
An AC voltage source is applied across an R-C circuit. Angular frequency of the source is omega , resistance is R and capacitance is C. The current registered is I. If now the frequency of source is changed to omega/2 (but maintaining the same voltage), the current in the circuit is found to be two third. calculate the ratio of reactance to resistance at the original frequency omega .
An a.c. source of angular frequency omega is fed across a resistor R and a capacitor C in series. The current registered is I. If now the frequency of the source is changed to omega//3 (but maintaining the same voltage), the current in the circuit is found to be halved. calculate the ratio of reactance to resistance at the original frequency omega .
AC voltage source (V, omega) is applied across a parallel LC circuit as shown in figure. Find the impedance of the circuit and phase of current.
A series LCR circuit consists of an inductor L a capacitor C and a resister R connected across a source of emf epsilon = epsilon_(0) sin omegat. When omegaL = (1)/(omegaC) the current in the circuit is l_(0) and if angular frequency of the source is changed to omega, the current in the circuit becoms (l_(0)/(2) then the value of |omega'L-(1)/(omega'C)| is
A 50 Hz AC source of 20 V is connected across R and C as shown in figure. The voltage across R is 12 V . The voltage across C is
An ac source of angular frequency omega is fed across a resistor R and a capacitor C in series. The current registered is I. If now the freqency of source is chaged to (omega)//3 (but maintainging the same voltage), the current in the circuit is found to be halved. Calculate the ration of hte reactance to resistance at the original frequency omega .
Consider in L-C-R circuit as shown in figureure with an AC source of peak value V_0 and angular frequency omega . Then the peak value of current through the AC .
