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An ac voltage source V=V(0) sin omega t ...

An `ac` voltage source `V=V_(0) sin omega t` is connected across a resistance `R` and capacitance `C` as shown in figure.It is given that `R=1/(omegaC)`.The peak current is `I_(0)`. If the angular frequency of the voltage source is changed to `omega/sqrt3` keeping `R` and `C` fixed, then the new peak current in the circuit in the circuit is:

A

`(I_(0))/(2)`

B

`(I_(0))/(sqrt2)`

C

`(I_(0))/(sqrt3)`

D

`(I_(0))/(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • An ac source of voltage V=V_(m)sin omega t is connected across the resistance R as shown in figure. The phase relation between current and voltage for this circuit is

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