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If 1/(sqrt(2011+sqrt(2011^2-1)))=sqrtm-s...

If `1/(sqrt(2011+sqrt(2011^2-1)))=sqrtm-sqrtn` where m and n are positive integers , what is the value of m + n.

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To solve the equation \( \frac{1}{\sqrt{2011 + \sqrt{2011^2 - 1}}} = \sqrt{m} - \sqrt{n} \), where \( m \) and \( n \) are positive integers, we will follow these steps: ### Step 1: Simplify the Left Side We start with the expression on the left side: \[ \frac{1}{\sqrt{2011 + \sqrt{2011^2 - 1}}} \] ### Step 2: Rationalize the Denominator To simplify this expression, we will rationalize the denominator. We multiply the numerator and denominator by \( \sqrt{2011 - \sqrt{2011^2 - 1}} \): \[ \frac{\sqrt{2011 - \sqrt{2011^2 - 1}}}{\sqrt{(2011 + \sqrt{2011^2 - 1})(2011 - \sqrt{2011^2 - 1})}} \] ### Step 3: Simplify the Denominator Using the difference of squares: \[ (2011 + \sqrt{2011^2 - 1})(2011 - \sqrt{2011^2 - 1}) = 2011^2 - (2011^2 - 1) = 1 \] Thus, the expression simplifies to: \[ \sqrt{2011 - \sqrt{2011^2 - 1}} \] ### Step 4: Set the Expression Equal to the Right Side Now we have: \[ \sqrt{2011 - \sqrt{2011^2 - 1}} = \sqrt{m} - \sqrt{n} \] ### Step 5: Square Both Sides Squaring both sides gives: \[ 2011 - \sqrt{2011^2 - 1} = m + n - 2\sqrt{mn} \] ### Step 6: Rearranging the Equation Rearranging gives: \[ \sqrt{2011^2 - 1} = m + n - 2011 + 2\sqrt{mn} \] ### Step 7: Identify \( m \) and \( n \) To express \( \sqrt{2011 - \sqrt{2011^2 - 1}} \) in the form \( \sqrt{m} - \sqrt{n} \), we can rewrite: \[ 2011 - \sqrt{2011^2 - 1} = 2011 - \sqrt{(2011 - 1)(2011 + 1)} = 2011 - \sqrt{2010 \cdot 2012} \] This can be expressed as: \[ 2011 - \sqrt{2011^2 - 1} = 1006 + 1005 - 2\sqrt{1006 \cdot 1005} \] Thus, we have \( m = 1006 \) and \( n = 1005 \). ### Step 8: Calculate \( m + n \) Finally, we find: \[ m + n = 1006 + 1005 = 2011 \] ### Final Answer The value of \( m + n \) is \( \boxed{2011} \). ---
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RESONANCE ENGLISH-NUMBER THEORY-Exercise -2 (PART - I)
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