Home
Class 12
PHYSICS
The position vector of a particle change...

The position vector of a particle changes with time according to the direction `vec(r)(t)=15 t^(2)hati+(4-20 t^(2))hatj`. What is the magnitude of the acceleration at t=1?

Text Solution

Verified by Experts

The correct Answer is:
50

`vec(r ) = 15 t^(2) hat(i) + (4 - 20 t^(2)) hat(j)`
`(vec(dt^(2)))/(dt^(2)) = 30 hat(i) + (- 40) hat(j), a = 50 m//sec^(2)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • JEE MAIN REVISION TEST 11 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION - 2)|5 Videos
  • JEE MAIN REVISION TEST -17 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS|25 Videos
  • JEE MAIN REVISION TEST 5 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

Similar Questions

Explore conceptually related problems

vec(r)=15t^(2)i+(20-20t^(2))j find magnitude of acceleration at t=1 sec.

The position x of a particle varies with time t according to the relation x=t^3+3t^2+2t . Find the velocity and acceleration as functions of time.

The position vector of a particle is r = a sin omega t hati +a cos omega t hatj The velocity of the particle is

The position vector of a particle is determined by the expression vec r = 3t^2 hat i+ 4t^2 hat j + 7 hat k . The displacement traversed in first 10 seconds is :

The position vector of a particle is given by vec r = (2t hati+5t^(2)hatj)m (t is time in sec). Then the angle between initial velocity and initial acceleration is

The velocity of an object is given by vecv = ( 6 t^(3) hati + t^(2) hatj) m//s . Find the acceleration at t = 2s.

The velocity of an object is given by vecv = ( 6 t^(3) hati + t^(2) hatj) m//s) . Find the acceleration at t = 2s.

Position vector of a particle is expressed as function of time by equation vec(r)=2t^(2)+(3t-1) hat(j) +5hat(k) . Where r is in meters and t is in seconds.

The angular position of a point over a rotating flywheel is changing according to the relation, theta = (2t^3 - 3t^2 - 4t - 5) radian. The angular acceleration of the flywheel at time, t = 1 s is

The displacement y(t) of a particle depends on time according in equation y(t)=a_(1)t-a_(2)t^(2) . What is the dimensions of a_(1) and a_(2) ?