A solid sphere of mass `m &` rdius `R` is divided in two parts of `m` mass `(7m)/(8) & (m)/(8)`, and converted to a disc of radius `2R &` solid sphere of radius `'r'` respectively. Find `(I_(1))/(I_(2))` , If `I_(1) & I_(2)` are moment of inertia of disc `&` solid sphere respectively

Answer

140

Explanation

`I_(1) = (7M)/(8) xx ((2R)^(2))/(2) = (7)/(4) MR^(2)`
`I_(2) = (2)/(5) xx ((M)/(8)) xx ((R)/(2))^(2)` (Radius of new sphere `= (R)/(2)`) `= (1)/(80) MR^(2)`
`I_(1) : I_(2) = 140`