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The velocity time graph of a particle ex...

The velocity time graph of a particle executing SHM is shown. The maximum acceleration of the particle is `npi m//s^2`, where n is______.

Text Solution

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The correct Answer is:
25
`T = 2 xx 0.4 "sec" `
`omega = (2pi)/T = (2pi)/(0.8)`
`V_("max") = A omega implies A = (V_("max"))/(omega) = 10/(2pi) xx 0.8 = (theta)/(2pi) m`
Now `a_("max") = A omega^2 = 8/(2pi) xx (4pi^2)/(0.8 xx 0.8) = (20 pi)/(0.8) = (20pi)/(0.8) = 25 pi m//s^2` .
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