Home
Class 12
PHYSICS
The velocity time graph of a particle ex...

The velocity time graph of a particle executing SHM is shown. The maximum acceleration of the particle is `npi m//s^2`, where n is______.

Text Solution

Verified by Experts

The correct Answer is:
25
`T = 2 xx 0.4 "sec" `
`omega = (2pi)/T = (2pi)/(0.8)`
`V_("max") = A omega implies A = (V_("max"))/(omega) = 10/(2pi) xx 0.8 = (theta)/(2pi) m`
Now `a_("max") = A omega^2 = 8/(2pi) xx (4pi^2)/(0.8 xx 0.8) = (20 pi)/(0.8) = (20pi)/(0.8) = 25 pi m//s^2` .
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST - 18

    VMC MODULES ENGLISH|Exercise PHYSICS - SECTION 2|5 Videos

  • JEE MAIN REVISION TEST - 13

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

  • JEE MAIN REVISION TEST - 19

    VMC MODULES ENGLISH|Exercise PHYSICS|25 Videos

Similar Questions

Explore conceptually related problems

The velocity - time graph of a particle is as shown in figure

Velocity-time graph of a particle executing SHM is shown in figure. Select the correct alternative(s).

The velovity-time graph of a particle moving in a straitht line is shown in . The acceleration of the particle at t=9 s is. .

Velocity-time graph of a particle in SHM is as shown in figure. Match the following

The velocity –position graph of a particle moving along a straight line is shown. Then acceleration of the particle at s = 15 m is :

Displacement-time graph of a particle executing SHM is as shown The corresponding force-time graph of the particle can be

velocity time graph of a particle is shown in figure. Find displacement of the particle.

Displacement time(x-t) graph of a particle executing S.H.M is shown In the figure.The equation of S.H.M is given by

The velocity - time graph is shown in the figure, for a particle. The acceleration of particle is

Accleration-time graph of a particle executing SHM is as shown in figure. Select the correct alternatives(s).