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A particle starts travelling on a circle...

A particle starts travelling on a circle with constant tangential acceleration. The angle between velocity vector and acceleration vector, at the moment when particle completes half the circular track. Is

A

`tan ^(-1) (2pi)`

B

`tan^(-1) (pi)`

C

`tan^(-1) (3pi)`

D

zero

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The correct Answer is:
To solve the problem, we need to analyze the motion of a particle traveling along a circular path with constant tangential acceleration. We will determine the angle between the velocity vector and the acceleration vector when the particle completes half of the circular track. ### Step-by-Step Solution: 1. **Understanding the Motion**: - The particle is moving in a circular path with a constant tangential acceleration (denoted as \( a_T \)). - As the particle moves, it experiences two types of acceleration: - Tangential acceleration (\( a_T \)), which is responsible for changing the speed of the particle along the circular path. - Centripetal acceleration (\( a_C \)), which is directed towards the center of the circle and is responsible for changing the direction of the velocity vector. 2. **Position at Halfway Point**: - When the particle completes half of the circular track, it will be at the point directly opposite its starting point on the circle. - At this point, the velocity vector (\( \vec{v} \)) will be tangent to the circle and directed along the horizontal axis (assuming the starting point is at the top of the circle). 3. **Direction of Accelerations**: - The tangential acceleration (\( a_T \)) will also be directed along the tangent to the circle at the halfway point, which is in the same direction as the velocity vector. - The centripetal acceleration (\( a_C \)) will be directed towards the center of the circle. 4. **Angle Between Velocity and Acceleration**: - Since the tangential acceleration (\( a_T \)) is in the same direction as the velocity vector (\( \vec{v} \)), the angle between them is \( 0^\circ \). - The centripetal acceleration (\( a_C \)) does not affect the angle between the velocity and tangential acceleration since it is always directed towards the center of the circle. 5. **Conclusion**: - The angle between the velocity vector and the tangential acceleration vector when the particle completes half the circular track is \( 0^\circ \). ### Final Answer: The angle between the velocity vector and the acceleration vector at the moment when the particle completes half the circular track is \( 0^\circ \). ---

To solve the problem, we need to analyze the motion of a particle traveling along a circular path with constant tangential acceleration. We will determine the angle between the velocity vector and the acceleration vector when the particle completes half of the circular track. ### Step-by-Step Solution: 1. **Understanding the Motion**: - The particle is moving in a circular path with a constant tangential acceleration (denoted as \( a_T \)). - As the particle moves, it experiences two types of acceleration: - Tangential acceleration (\( a_T \)), which is responsible for changing the speed of the particle along the circular path. ...
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