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Two buses A and B are moving around conc...

Two buses A and B are moving around concentric circular pathe of radii `r_(A)` and `r_(B)` If the two buses complete the circular paths in the sme time. The ratio on their linear speeds is

A

1

B

`r_A //r_B`

C

`r_B//r_A`

D

none of the above

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio of the linear speeds of two buses A and B moving along concentric circular paths of radii \( r_A \) and \( r_B \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: - We have two buses, A and B, moving in circular paths with radii \( r_A \) and \( r_B \) respectively. - Both buses complete their circular paths in the same amount of time. 2. **Define Linear Speed**: - The linear speed \( v \) of an object moving in a circular path is given by the formula: \[ v = \frac{2\pi r}{T} \] where \( r \) is the radius of the circular path and \( T \) is the time period (the time taken to complete one full revolution). 3. **Set Up the Equations**: - For bus A, the linear speed \( v_A \) can be expressed as: \[ v_A = \frac{2\pi r_A}{T} \] - For bus B, the linear speed \( v_B \) can be expressed as: \[ v_B = \frac{2\pi r_B}{T} \] 4. **Find the Ratio of Linear Speeds**: - To find the ratio of the linear speeds \( \frac{v_A}{v_B} \), we can divide the two equations: \[ \frac{v_A}{v_B} = \frac{\frac{2\pi r_A}{T}}{\frac{2\pi r_B}{T}} \] - The \( 2\pi \) and \( T \) cancel out: \[ \frac{v_A}{v_B} = \frac{r_A}{r_B} \] 5. **Conclusion**: - Therefore, the ratio of the linear speeds of buses A and B is: \[ \frac{v_A}{v_B} = \frac{r_A}{r_B} \] ### Final Answer: The ratio of their linear speeds is \( \frac{r_A}{r_B} \).
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