Calcium carbonate reacts with aqueous HCI to give `CaCI_(2)` and `CO_(2)`, write the reaction.

Options

A. 0.1 g
B. 0.5 g
C. 1.5 g
D. 0.94 g

Answer

To write the balanced chemical reaction for the reaction between calcium carbonate and hydrochloric acid, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Calcium Carbonate (CaCO₃)
- Hydrochloric Acid (HCl)

2. **Identify the Products**:
- Calcium Chloride (CaCl₂)
- Carbon Dioxide (CO₂)
- Water (H₂O)

3. **Write the Unbalanced Equation**:
- CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O

4. **Balance the Equation**:
- Count the number of atoms of each element on both sides of the equation.
- On the left side, we have:
- 1 Calcium (Ca)
- 1 Carbon (C)
- 3 Oxygens (O)
- 1 Hydrogen (H)
- 1 Chlorine (Cl)
- On the right side, we have:
- 1 Calcium (Ca)
- 1 Carbon (C)
- 2 Oxygens (O) from CO₂ and 1 from H₂O = 3 Oxygens total
- 2 Hydrogens (H) from H₂O
- 2 Chlorines (Cl) from CaCl₂

5. **Adjust Coefficients to Balance**:
- To balance the hydrogen and chlorine, we need 2 HCl:
- CaCO₃ + 2 HCl → CaCl₂ + CO₂ + H₂O

6. **Final Balanced Equation**:
- The balanced chemical equation is:
- CaCO₃ + 2 HCl → CaCl₂ + CO₂ + H₂O

### Final Answer:
The balanced chemical reaction is:
\[ \text{CaCO}_3 + 2 \text{HCl} \rightarrow \text{CaCl}_2 + \text{CO}_2 + \text{H}_2\text{O} \]