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From 200 mg of CO(2), 10^(21) molecules ...

From `200 mg` of `CO_(2), 10^(21)` molecules are removed. How many grams and moles of `CO_(2)` are left.

A

`2.88 xx 10^(-3)`

B

`1.44 xx 10^(-3)`

C

`3.68 xx 10^(-3)`

D

`5.42 xx 10^(-3)`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • If 10^(21) molecules are removed from 200 mg of CO_(2), the number of moles of CO_(2) left is

    A
    `2.88xx10^(-3)`
    B
    `28.8xx10^(-3)`
    C
    `0.288xx10^(-3)`
    D
    `1.66xx10^(-2)`
  • How many number of CO_(2) molecules are required to synthesise one molecule of glucose during C_(3) cycle?

    A
    One
    B
    Three
    C
    Six
    D
    Five
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