Home
Class 12
CHEMISTRY
250 " mL of " x M solution and 500 " mL ...

250 " mL of " x M solution and 500 " mL of " y M solution of a solute are mixed and diluted to 2L to produce a final concentration of 1.6 M. If `x:y=5:4`, calculate x and y.

A

3.94, 4.92

B

4.92, 4.92

C

4.92, 3.94

D

3.94 , 3.94

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPT OF CHEMISTRY

    VMC MODULES ENGLISH|Exercise IMPECCABLE|49 Videos
  • SOME BASIC CONCEPT OF CHEMISTRY

    VMC MODULES ENGLISH|Exercise ENABLE|49 Videos
  • REVISION TEST-2 JEE

    VMC MODULES ENGLISH|Exercise CHEMISTRY|25 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    VMC MODULES ENGLISH|Exercise IN - CHAPTER EXERCISE - H|8 Videos

Similar Questions

Explore conceptually related problems

250 mL of x M solution and 500 mL of y M solution of a solute A are mixed and diluted to 2 litre to produce a final concentration of 1.6 M. if x : y = 5 : 4 calculate x and y .

500 ml of aM and 500 ml of bM solution of a solute are mixed and diluted to 2 litre to prepare a solution of 1.5 M. If a and b are in the ratio 2 : 1, then the value of a is.

200 ml of water is added of 500 ml of 0.2 M solution. What is the molarity of this diluted solution?

500 ml of 2M NaCl solution was mixed with 200 ml of 2 M NaCl solution. Calculate the molarity of NaCl in final solution

When 100 ml of M/10 NaOH solution and 50 ml of M/5 HCI solution are mixed, the pH of resulting solution would be

200 mL of 1 HCl, is mixed with 300 mL of 6 M and the final solution is diluted to 1000 mL.calculate molar concentration of [H^(+) ] ion .

10mL of 2(M) NaOH solution is added to 200mL of 0.5 (M) of NaOH solution. What is the final concentration?

If 250 ml of 0.25 M NaCl solution is diluted with water to a volume of 500 ml, the new concentration of solution is:

The number of moles of the solute present in 500 ml of 0.6M solution is:

The number of moles of the solute present in 500 ml of 0.5M solution is:

VMC MODULES ENGLISH-SOME BASIC CONCEPT OF CHEMISTRY-EFFICIENT
  1. 250 " mL of " x M solution and 500 " mL of " y M solution of a solute ...

    Text Solution

    |

  2. 2.68 xx 10^(-3) moles of a solution containing an ion A^(n+) require 1...

    Text Solution

    |

  3. 30 ml of N/10 HC1 is required to neutralize 50 ml of a sodium carbonat...

    Text Solution

    |

  4. Molecular mass of KOH is

    Text Solution

    |

  5. Two acids A and B are titrated separately each time with 25 " mL of " ...

    Text Solution

    |

  6. In an ore the oxidisable is Sn^(2+). This is ore is titrated with a di...

    Text Solution

    |

  7. A sample of gaseous hydrocarbon occupying 1.12 "litre" at NTP, when co...

    Text Solution

    |

  8. A sample of hard water contains 20 mg of Ca^(2+) ions per litre. How m...

    Text Solution

    |

  9. A drug marijuana owes its activity to tetrahydrocannabinol, which cont...

    Text Solution

    |

  10. How much NaNO3 must be weighed out to make 50 ml of an aqueous solutio...

    Text Solution

    |

  11. A silver coin weighing 2.5 gm was dissolved in HNO3 and then further t...

    Text Solution

    |

  12. Molecular mass of carbon dioxide is

    Text Solution

    |

  13. Molecular mass of methane is

    Text Solution

    |

  14. 5 gm of K2 SO4 solution were dissolved in 250 ml of water. How many ml...

    Text Solution

    |

  15. Molecular mass of NaOH is

    Text Solution

    |

  16. Gastric juice contains about 3.0 g HCI per litre. If a person produces...

    Text Solution

    |

  17. Molecular mass of H(2)O(2) is

    Text Solution

    |

  18. Calculate the number of moles in 22g of helium.

    Text Solution

    |

  19. The formula weight of an acid is 82 amu .In titration 100 cm^(3) of a ...

    Text Solution

    |

  20. Calculate the number of moles in 69g of sodium.

    Text Solution

    |