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Calculate the PH of the resultant mixtur...

Calculate the PH of the resultant mixture :
10 mL of 0.1 M` H_2SO_4 + 10 mL ` of 0.1 M KOH

Text Solution

Verified by Experts

Here, `n_(a)M_(a)V_(a) ( = 2 xx 0.1 xx 10) gt n_(b)M_(b)V_(2) ( = 1 xx 0.1 xx 10 = 1)` , therefore
`pH = - log [(2-1)/(10+10)] = 1.3 `
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