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Calculate the PH of the resultant mixtur...

Calculate the PH of the resultant mixture :
10 mL of 0.2 M ` Ca(OH)_2` + 25 mL of 0.1 M `HCl `

Text Solution

Verified by Experts

`pOH = - log [((2xx0.2 xx 10)-(1xx0.1xx25))/(10+25)] = 1.64`
` :' pH + pOH = 14 rArr pH = 14 - pOH = 14 - 1.64 = 12.36`
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