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The time period of a freely suspended ma...

The time period of a freely suspended magnet is 4 seconds. If it is broken in length into two equal parts and one part is suspended in the same way, then its time period will be

A

4s

B

2s

C

0.5s

D

0.25s

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze how the time period of a freely suspended magnet changes when it is cut into two equal parts. ### Step-by-Step Solution: 1. **Understanding the Given Data**: - The initial time period \( T \) of the magnet is given as 4 seconds. 2. **Cutting the Magnet**: - When the magnet is cut into two equal parts, the length of each part becomes half of the original length. If we denote the original length as \( L \), then the new length \( L' = \frac{L}{2} \). 3. **Magnetic Dipole Moment**: - The magnetic dipole moment \( \mu \) of a magnet is given by the product of its pole strength \( p \) and its length \( L \): \[ \mu = p \cdot L \] - After cutting the magnet, the new magnetic dipole moment \( \mu' \) for one part becomes: \[ \mu' = p \cdot \frac{L}{2} = \frac{\mu}{2} \] 4. **Moment of Inertia**: - The moment of inertia \( I \) for a magnet fixed at its center is given by: \[ I = \frac{mL^2}{12} \] - When the magnet is cut into two equal parts, the mass of each part becomes \( \frac{m}{2} \) and the new length is \( \frac{L}{2} \). Therefore, the new moment of inertia \( I' \) becomes: \[ I' = \frac{\frac{m}{2} \left(\frac{L}{2}\right)^2}{12} = \frac{m}{2} \cdot \frac{L^2}{4} \cdot \frac{1}{12} = \frac{mL^2}{96} = \frac{I}{8} \] 5. **Time Period Formula**: - The time period \( T \) of a magnet suspended in a magnetic field is given by: \[ T = 2\pi \sqrt{\frac{I}{\mu B}} \] - For the new part, the time period \( T' \) becomes: \[ T' = 2\pi \sqrt{\frac{I'}{\mu' B}} = 2\pi \sqrt{\frac{\frac{I}{8}}{\frac{\mu}{2} B}} = 2\pi \sqrt{\frac{I}{8} \cdot \frac{2}{\mu B}} = 2\pi \sqrt{\frac{I}{\mu B}} \cdot \frac{1}{\sqrt{4}} = \frac{T}{2} \] 6. **Calculating the New Time Period**: - Since the original time period \( T \) is 4 seconds, the new time period \( T' \) will be: \[ T' = \frac{4}{2} = 2 \text{ seconds} \] ### Final Answer: The new time period of the suspended magnet after cutting it into two equal parts is **2 seconds**. ---
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