Home
Class 12
PHYSICS
At t=0, a particle at (1,0,0) moves towa...

At `t=0`, a particle at `(1,0,0)` moves towards point `(4,4,12)` with a constant velocity of magnitude `65m//s`. The position of the particle is measured in metres and time in sec. Assuming constant velocity, the position of the particle at `t=2 sec` is `:`

Text Solution

Verified by Experts

The correct Answer is:
31
`x=x_(i)+Deltax`
`Deltax=v_(x)Deltat" "(Deltat=2sec)`
`v_(x)=(x_(f)-x_(i))/(|Deltat|) and |Delta t|=(sqrt((4-1)^(2)+4^(2)+12^(2)))/(65)=(1)/(5)sec: x=5xx3xx2+1=31`
Promotional Banner

Topper's Solved these Questions

  • MOCK TEST 8

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

  • MOCK TEST 7

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

  • MOCK TEST 9

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

Similar Questions

Explore conceptually related problems

When at t = 0, a particle at (1, 0, 0) moves towards (4, 4, 12) with a constant speed of 65 m/s. The position of the particle is measured in meters and time in sec. Assuming constant velocity, the x co-ordinate of the particle at t = 2 sec is:

A particle starts from rest and moves with an acceleration of a={2+|t-2|}m//s^(2) The velocity of the particle at t=4 sec is

A particle starts from rest and moves with an acceleration of a={2+|t-2|}m//s^(2) The velocity of the particle at t=4 sec is

If the velocity of a particle moving along x-axis is given as v=(3t^(2)-2t) and t=0, x=0 then calculate position of the particle at t=2sec.

A particle of mass m is moving along the line y-b with constant acceleration a. The areal velocity of the position vector of the particle at time t is (u=0)

A particle starts moving with constant, velocity v=2(m)/(s) , from position x=5m The position time graph will be

V_(x) is the velocity of a particle of a particle moving along the x- axis as shown. If x=2.0m at t=1.0s , what is the position of the particle at t=6.0s ?

A particle is moving along x-direction with a constant acceleration a. The particle starts from x=x_0 position with initial velocity u. We can define the position of the particle with time by the relation x=x_0+ut+(1)/(2)at^2 plot the position of the particle in relation with time is following situations (i) If initial position of the particle is on negativ x-axis, initial velocity is positive and acceleration is negative. (ii) If initial position is positive, initial velocity is negative and acceleration is positive.

Two particles A and B are revolving with constant angular velocity on two concentric circles of radius 1m and 2m respectively as shown in figure. The positions of the particles at t = 0 are shown in figure. The positions of the particles at t=0 are shown in figure. if m_(A)=2kg, m_(B)= 1kg and vec(P)_(A) and vec(P)_(B) are linear momentum of the particle then what is the maximum value of |vec(P)_(A)+vec(P)_(B)| in kg-m/sec in subsequent motion of two particles.

A particle movesin the X-Y plane with a constasnt acceleration of 1.5 m/s^2 in the direction making an angle of 37^0 with the X-axis.At t=0 the particle is at the orign and its velocity is 8.0 m/s along the X-axis. Find the velocity and the position of the particle at t=4.0 s.