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"cos" x *"cos" 2x* "cos" 3x , find d y/...

`"cos" x *"cos" 2x* "cos" 3x` , find d y/ d x

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To find the derivative of the function \( y = \cos x \cdot \cos 2x \cdot \cos 3x \), we will use logarithmic differentiation. Here’s a step-by-step solution: ### Step 1: Take the logarithm of both sides We start by taking the natural logarithm of both sides: \[ \ln y = \ln(\cos x \cdot \cos 2x \cdot \cos 3x) \] ...
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