Sodium bicarbonate reacts with salicylic acid to form

Options

A. `C_6H_5ONa`
B.
C.
D.

Answer

To determine what sodium bicarbonate (NaHCO3) reacts with salicylic acid to form, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Sodium bicarbonate (NaHCO3)
- Salicylic acid (C7H6O3)

2. **Write the Structure of Salicylic Acid**:
- Salicylic acid has a hydroxyl group (-OH) and a carboxylic acid group (-COOH) attached to a benzene ring. The structure can be represented as:
```
OH
|
C6H4 - C(=O)OH
```

3. **Understand the Reaction**:
- Sodium bicarbonate is a weak base and will react with the acidic hydrogen of the carboxylic group in salicylic acid. This reaction will lead to the formation of a salt, carbon dioxide (CO2), and water (H2O).

4. **Write the Reaction Equation**:
- The reaction can be summarized as follows:
```
C7H6O3 (salicylic acid) + NaHCO3 → C7H5O3Na (sodium salicylate) + CO2 + H2O
```

5. **Identify the Product**:
- The main product formed from this reaction is sodium salicylate (C7H5O3Na).

6. **Check the Options**:
- Based on the reaction, the correct answer is sodium salicylate.

### Final Answer:
The reaction of sodium bicarbonate with salicylic acid forms sodium salicylate, carbon dioxide, and water.