Home
Class 12
CHEMISTRY
The quantity of electricity needed to be...

The quantity of electricity needed to be deposit `127.08 gm`. Of copper is

A

`1F`

B

4 coulombs

C

`4F`

D

1 ampers

Text Solution

Verified by Experts

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • D AND F BLOCK ELEMENTS

    SHARAM PUBLICATION|Exercise EXERCISE|72 Videos
  • GENERAL PRINCIPLES AND PROCESS OF ISOLATION OF ELEMENTS

    SHARAM PUBLICATION|Exercise EXERCISE|82 Videos

Similar Questions

Explore conceptually related problems

Calculate the quantity of electricity required to deposit 0.108gm. of silver from AgNO_3 soln. (At. Mass of Ag=108).

Find the quantity of electricity needed to plate a metal of 100 cm^2 area and 10^-2cm thickness using CuSO_4 solution. (density of copper = 9.94 gm//cm^3 and atomic mass = 63.5)

Knowledge Check

  • Quantity of electricity is measured in :

    A
    ampere sec
    B
    ampere
    C
    `ampere^(-1)`
    D
    `ampere^(-1)` sec
  • Quantity of electricity is measured in :

    A
    ampere sec
    B
    ampere
    C
    `ampere^(-1)`
    D
    `ampere^(-1)` sec
  • The quantity of electricity needed to liberated 0.5 g equivalent of an element, during electrolysis is

    A
    48250 Coulombs
    B
    48250 Faraday
    C
    19300 Coulombs
    D
    19300 Faraday
  • Similar Questions

    Explore conceptually related problems

    _____ quantity of electricity will deposit 10.8 gm of ‘Ag’ at cathode from a AgNO_3 solution.

    What amount of electricity is required to deposite 1mole copper from a solution of CuSO_4 ?

    what amount of electricity is required to deposit 1 more copper from a solution of CuSO_(4)

    Saltas of A (atomic weigh 48) were electrolysed under identical condition using the same quantity of electricity. It was found that when 2.1 g of A was deposited, the eight of B and C deposited were 2.7 and 7.2 g. The valencies of A,B and C are respectively :

    Number of Faraday needed to deposit 0.1 mole of copper from Cu(II) sulphate solution are :