A crystal of lead (II) sulphide has NaCl structure. In this crystal, the shortest distance between the `Pb^(2+)` ion and `S^(2-)` ion is 297 pm. What is the length of the edge of the unit cell in lead sulphide ? Also, calculate the unit cell volume.
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The correct Answer is:
`a=5.9xx10^(-8)cm, V=2.096xx10^(-22)cm^(3)`
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